Comments on: Must be a better way to do this

By: HR

HR — Sun, 01 Apr 2007 17:08:58 +0000

Damned, I misspelled your name, sorry.

By: HR

HR — Sun, 01 Apr 2007 17:07:05 +0000

@Derrick: well, none of the snippets account for the user’s timezone, DST or the exact time the novel will be out but they get the job done, which I believe is the whole point of PHP right?

By: Maarten Manders

Maarten Manders — Sun, 18 Mar 2007 16:49:57 +0000

What about the PHP date class? Or the one in Zend Framework?

By: Derick

Derick — Sun, 18 Mar 2007 07:41:01 +0000

Everything that uses 86400 is flawed. Not every day is 86400 seconds unfortunately.

I don’t have a solution ready though

By: Rob...

Rob... — Sat, 17 Mar 2007 20:07:48 +0000

For Months, I’d do something like:

$finishYear = ‘2008′;
$finishMonth = ‘07′;
$thisYear = date(’Y');
$thisMonth = date(’m');
$numMonths = ((($finishYear - $thisYear) * 12) + $finishMonth) - $thisMonth;

(With a possible +1 depending on how you want to count!)

By: Aaron Wormus

Aaron Wormus — Sat, 17 Mar 2007 15:17:12 +0000

The reason why I went with the double strtotime, was because the last time I did this was counting months, which is more complex.

By: Rob...

Rob... — Sat, 17 Mar 2007 13:00:29 +0000

$april1st = gmmktime(0, 0, 0, 4, 1, 2007);
$now = gmmktime(0, 0, 0);
$days_remaining = ($april1st - $now) / 86400;

By: HR

HR — Sat, 17 Mar 2007 12:13:11 +0000

Erm, how about using the difference in seconds divided by the number of seconds per day?

$days = ceil((strtotime(’April 1, 2007′) - time()) / 86400);

if ($days > 0)
{
echo $days, (($days == 1) ? ‘ day’ : ‘ days’), ‘ left till you can buy Ancestor Novel’;
}
else
{
echo ‘Ancestor Novel is available NOW!’;
}